{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Warning" -1 7 1 {CSTYLE "" -1 -1 "Courier " 1 10 0 0 255 1 2 2 2 2 2 1 1 1 3 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 } {PSTYLE "Maple Output" -1 11 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 3 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Maple Plot " -1 13 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 } 3 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Normal" -1 256 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }3 1 0 0 0 0 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 20 "with(LinearAlgebra): " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 12 "with(plots):" }}{PARA 7 "" 1 "" {TEXT -1 50 "Warning, the name changecoords has been redefin ed\n" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 110 "First we will make a thr ee-dimensional plot containing some vectors. Try rotating the plot by \+ using the mouse." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 189 "i := a rrow(<1,0,0>, shape=arrow, color=red):\nj := arrow(<0,1,0>, shape=arro w, color=green):\nk := arrow(<0,0,1>, shape=arrow, color=blue):\ndispl ay(i, j, k, scaling=CONSTRAINED, axes=boxed);\n" }}{PARA 13 "" 1 "" {GLPLOT3D 277 277 277 {PLOTDATA 3 "6'-%'CURVESG6&7$7%$\"\"!F)F(F(7%$\" +++++5!\"*F(F(7%7%$\"+++++!)!#5$!+++++]!#6F(F*7%F0$\"+++++]F5F(-%&STYL EG6#%,PATCHNOGRIDG-%'COLOURG6&%$RGBG$\"*++++\"!\")F(F(-F$6&7$F'7%F(F+F (7%7%F(F0F3FG7%F(F0F7F9-F>6&F@F(FAF(-F$6&7$F'7%F(F(F+7%7%F(F7F0FP7%F(F 3F0F9-F>6&F@F(F(FA-%(SCALINGG6#%,CONSTRAINEDG-%*AXESSTYLEG6#%$BOXG" 1 2 0 1 10 0 2 1 1 2 1 1.000000 45.000000 45.000000 0 0 "Curve 1" "Curve 2" "Curve 3" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 99 "The vectors i, j , and k are linearly independent. This is because the only solution to the equation" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 256 "" 0 "" {TEXT -1 16 "ai + bj + ck = 0" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 0 "" 0 "" {TEXT -1 2 "is" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 256 "" 0 "" {TEXT -1 13 "a = b = c = 0" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 110 "(the 0 at the end of the equat ion is the zero vector and the zero at the end of the solution is the \+ number 0)." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 77 "Notice the vectors i, j, and k are NOT coplanar. In this sense \+ they point in " }{TEXT 256 20 "different directions" }{TEXT -1 1 "." } }{PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 219 "Consider the vectors a1 = <1, 0, 1>, a2 = <0, 1, 0>, and a3 = <1, 1, \+ 1>. Are these vectors linearly independent or linearly dependent? Thin k about it once the following plot is generated. Are the three vectors coplanar?" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 195 "a1 := arrow( <1,0,1>, shape=arrow, color=red):\na2 := arrow(<0,1,0>, shape=arrow, c olor=blue):\na3 := arrow(<1,1,1>, shape=arrow, color=green):\ndisplay( a1, a2, a3, scaling=CONSTRAINED, axes=FRAMED);" }}{PARA 13 "" 1 "" {GLPLOT3D 350 350 350 {PLOTDATA 3 "6'-%'CURVESG6&7$7%$\"\"!F)F(F(7%$\" +++++5!\"*F(F+7%7%$\"+.+++v!#5F($\"+.+++&)F2F*7%F3F(F0-%&STYLEG6#%,PAT CHNOGRIDG-%'COLOURG6&%$RGBG$\"*++++\"!\")F(F(-F$6&7$F'7%F(F+F(7%7%F($ \"+++++!)F2$!+++++]!#6FD7%F(FG$\"+++++]FKF6-F;6&F=F(F(F>-F$6&7$F'7%$\" +**********F2FUFU7%7%$\"+1mWYwF2FY$\"+yn52()F2FT7%$\"+)Q`NN)F2Fhn$\"+; K*GH(F2F6-F;6&F=F(F>F(-%(SCALINGG6#%,CONSTRAINEDG-%*AXESSTYLEG6#%&FRAM EG" 1 2 0 1 10 0 2 1 1 3 1 1.000000 78.000000 107.000000 0 0 "Curve 1 " "Curve 2" "Curve 3" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 219 "Conside r the vectors a1 = <1, 0, 1>, a2 = <0, 1, 0>, and a4 = <1,1, -1>. Are \+ these vectors linearly independent or linearly dependent? Think about \+ it once the following plot is generated. Are the three vectors coplana r?" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 196 "a1 := arrow(<1,0,1>, shape=arrow, color=red):\na2 := arrow(<0,1,0>, shape=arrow, color=blu e):\na4 := arrow(<1,1,-1>, shape=arrow, color=green):\ndisplay(a1, a2, a4, scaling=CONSTRAINED, axes=FRAMED);" }}{PARA 13 "" 1 "" {GLPLOT3D 304 304 304 {PLOTDATA 3 "6'-%'CURVESG6&7$7%$\"\"!F)F(F(7%$\"+++++5!\"* F(F+7%7%$\"+.+++v!#5F($\"+.+++&)F2F*7%F3F(F0-%&STYLEG6#%,PATCHNOGRIDG- %'COLOURG6&%$RGBG$\"*++++\"!\")F(F(-F$6&7$F'7%F(F+F(7%7%F($\"+++++!)F2 $!+++++]!#6FD7%F(FG$\"+++++]FKF6-F;6&F=F(F(F>-F$6&7$7%F(F($!\"!F)7%$\" +**********F2FX$!+**********F27%7%$\"+1mWYwF2Fhn$!+yn52()F2FW7%$\"+)Q` NN)F2F]o$!+;K*GH(F2F6-F;6&F=F(F>F(-%(SCALINGG6#%,CONSTRAINEDG-%*AXESST YLEG6#%&FRAMEG" 1 2 0 1 10 0 2 1 1 3 1 1.000000 63.000000 36.000000 0 0 "Curve 1" "Curve 2" "Curve 3" }}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 21 "Consider the equation" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 256 "" 0 "" {TEXT -1 22 "x*a1 + y*a2 + z*a4 = 0" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 64 "where x, y, and z are sca lars. This leads to the matrix equation" }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 256 "" 0 "" {TEXT -1 7 "Av = 0," }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 161 "where A is the matrix with col umns a1, a2, and a4 and v is the column vector with entries x, y, and \+ z (the 0 is the zero vector). Next find the determinant of A." }} {PARA 0 "" 0 "" {TEXT -1 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "A := Matrix([[1,0,1],[0,1,0],[1,1,-1]]);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"AG-%'RTABLEG6%\"))eJ>\"-%'MATRIXG6#7%7%\"\"\"\"\"!F .7%F/F.F/7%F.F.!\"\"%'MatrixG" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "Determinant(A);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#!\"#" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 222 "Since det(A) is not zero, the sys tem Av = 0 has a unique solution. Since v = 0 solves Av = 0, it must b e the unique solution. Therefore x = y = z = 0 and a1, a2, and a4 are \+ linearly independent- they point in sufficiently " }{TEXT 257 20 "diff erent directions" }{TEXT -1 1 "." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 71 "For a nonzero vector v, are the v ectors v and -v linearly independent?" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{MARK "12 0 0" 108 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }{RTABLE_HANDLES 11931588 }{RTABLE M7R0 I5RTABLE_SAVE/11931588X,%)anythingG6"6"[gl!"%!!!#*"$"$"""""!F'F(F'F'F'F(!""6" }